The potential energy function of a particle in a region of space is given as `U=(2xy+yz)` J Here x,y and z are in metre. Find the force acting on the particle at a general point P(x,y,z).

If the potential energy function of a particle is given by U=-(x^2+y^2+z^2) J, whre x,y and z are in meters. Find the force acting on the particle at point A(1m,3m,5m) .

The potential energy (in joules ) function of a particle in a region of space is given as: U=(2x^(2)+3y^(2)+2x) Here x,y and z are in metres. Find the maginitude of x compenent of force ( in newton) acting on the particle at point P ( 1m, 2m, 3m).

The potential energy of a partical of mass 2 kg moving in y-z plane is given by U=(-3y+4z)J where y and z are in metre. The magnitude of force ( in newton ) on the particle is :

The potential energy function of a particle due to some gravitational field is given by U=6x+4y . The mass of the particle is 1kg and no other force is acting on the particle. The particle was initially at rest at a point (6,8) . Then the time (in sec). after which this particle is going to cross the 'x' axis would be:

The potential energy of a particle of mass 5 kg moving in the x-y plane is given by U=(-7x+24y)J , where x and y are given in metre. If the particle starts from rest, from the origin, then the speed of the particle at t=2 s is

The potential energy of configuration changes in x and y directions as U=kxy , where k is a positive constant. Find the force acting on the particle of the system as the function of x and y.

The potential energy of a particle of mass 1 kg in a conservative field is given as U=(3x^(2)y^(2)+6x) J, where x and y are measured in meter. Initially particle is at (1,1) & at rest then:

[" 5.The potential energy function for a two dimensional force is "],[U=+2x^(3)-4x^(2)y+6y^(2)" where "U" is in joules,"x" and "y" are in metres.The force (in "N)],[" acting on particle at "(3m,2m)" is "(Ahat i+Bhat j)" newtons.Find "A+B?]