A body of mass `m` taken form the earth's surface to the height is equal to twice the radius `(R)` of the earth. The change in potential energy of body will be

A body of mass m is taken from the earth's surface to the height equal to twice the radius (R) of the earth.The change in potential energy of body will be

A body of mass m taken from the earth's surface to the height equal to the twice the earth radius R of the earth . The change in potential energy of the body will be

A body of mass m is lifted up from the surface of earth to a height three times the radius of the earth R . The change in potential energy of the body is

A body of mass m is lifted up from the surface of earth to a height three times the radius of the earth . The change in potential energy of the body is (g - gravity field at the surface of the earth )

A body of mass m is placed on the earth's surface . It is taken from the earth's surface to a height h = 3 R when R is the radius of the earth. The change in gravitational potential energy of the body is

A body of mass m is taken from earth surface to the height h equal to radius of earth, the increase in potential energy will be

The acceleration due to gravity on the surface of the earth is g. If a body of mass m is raised from the surface of the earth to a height equal to the radius R of the earth, then the gain in its potential energy is given by

A body of mass m is lifted from the surface of earth of height equal to R//3 where R is the radius of earth, potential energy of the body increases by

When a body id lifted from surface of earth height equal to radius of earth, then the change in its potential energy is