`2(b ccosA+c acosB+a bcosC)=a^2+b^2+c^2`

In DeltaABC , prove that: c(acosB-b cosA)=a^(2)-b^(2)

In any DeltaABC , prove that a(bcosC-c cosB)=(b^(2)-c^(2))

With usual notatons , in triangle ABC , prove that a(bcosC-c cos B)=b^2-c^2 .

In a triangle ABC , if a,b,c are the sides opposite to angles A , B , C respectively, then the value of |{:(bcosC,a,c cosB),(c cosA,b,acosC),(acosB,c,bcosA):}| is

If a^2 + b^2 + c^2 = 2(a -b -c)- 3 ,then the value of (a- b + c) is यदि a^2 + b^2 + c^2 = 2(a -b -c)- 3 तो (a- b + c) का मान है-

Suppose A, B, C are defined as A=a^2b+a b^2-a^2c-a c^2, B=b^2c+b c^2-a^2b-a b^2, a n dC=a^2c+a c^2-b^2c-b c^2, w h e r ea > b > c >0 and the equation A x^2+B x+C=0 has equal roots, then a ,b ,c are in AdotPdot b. GdotPdot c. HdotPdot d. AdotGdotPdot

Prove: |(a^2,b c, a c+c^2),(a^2+a b,b^2,a c ),(a b,b^2+b c,c^2)|=4a^2b^2c^2

In triangleABC, (cosA)/(c cosB+bcosC)+(cosB)/(acosC+ccosA)+(cosC)/(acosB+bcosA)=

In a triangle ABC , acosB + b cosC + c cosA =(a+b+c)/2 then

In DeltaABC , prove that: a(bcosC-(c)cosB)=b^(2)-c^(2)