In the show arrangement mass of A=1 kg, mass of B= 2kg. Coefficient of friction between A and B =0.2

There is no friction between B and ground. The frictional force exerted by A on B equals.

In the arrangement shown in figure, coefficient of friction between the two blocks is mu=1//2 . The force of friction acting between

A block A with mass 100kg is resting on another block B of mass 200kg. As shown in figure a horizontal rope tied to a wall hold it. The coefficient of friction between A and B is 0.2 while coefficient of friction between B and the ground is 0.3 . the minimum required force F to start moving B will be.

A long conveyer belt moves with a constant velocity of 8 ms^(-1) .Two blockA and B each of mass 2kg are placed gently on the belt with B on A, initail velocity of block is zero Coefficient of friction between A and belt is 0.1 There is no friction between A and B length of A is 4m If the coefficient of friction between the block B and belt is 0.4 Find the separation between the two block when B come to rest w.r.t. belt

A is a 100kg block, and B is a 200kg block. As shown in figure the block A is attached to a string tied to a wall. The coefficient of friction between A and B is 0.2 and the coefficient of fricition between B and floor is 0.3. Then calculate the minimum force required to move the block B. (take g=10m//s^(2) ).

Two small blcok m=2kg each kept on wedge of mass 12 kg . There is no friction between blocks and wedge coefficient of friction between wedge and ground in mu=0.3 . Calculate frictional force by ground on wedge.

Consider the shown arrangement. The coefficient of friction between the two blocks is 0.5 . There is no friction between the 4 kg block and of 12 N is applied on the 2 kg block as shown in the figure, the acceleration of the 4 kg block would be

Block A of mass 2kg is placed over a block B of mass 8kg . The combination is placed on a rough horizontal surface. If g=10ms^(-2) , coefficient of friction between B and floor =0.5 , coefficient of friction between B and floor =0.5 , coefficient of friction between A and B=0.4 and a horizontal force of 10N is applied on 8kg block, then the force of friction between A and B is.

A block A of mass 200 kg rest on a block B of mass 300 kg . A is tied with a horizontal string to a wall. Coefficient of friction between A and B is 0.25 and that between B and floor is 0.2 . The horizontal force F needed to move the block B is

A block A of mass M rests on a wedge B of mass 2M and inclination theta . There is sufficient friction between A and B so that A does not slip on B. If there is no friction between B and ground, the compression in spring is