A straight section `PQ` of a circuit lise along the `X`-axis from `x=-a/2` to `x=a/2` and carriers a steady current `i`. The magnetic field due to the section `PQ` at a point `X=+a` will be

Magnetic field at point O due to straight conductor PQ is

A long straight wire of a circular cross-section of radius a carries a steady current I. The current is uniformly distributed across the cross-section. Apply Amperes circuital law to calculate the magnetic field at a point at distance r in the region for (i) rlta and (ii) rgta .

AbB is a section of a straight wire carrying a current I . P is a point at a distance d from AB . The magnetic field at P due to AB has magnitude

A straight thick long wire of uniform cross-section of radius 5cm is carrying a steady current 5A . Calculate the magnetic field at a point 2cm from the axis of wire, well inside the wire.

Write Ampere's circuital law.A long straight wire of a circular cross section (radius a ) carrying steady current.Current is uniformly distributed in the wire.Calculate magnetic field inside the region (r lt a) in the wire.

A long, straight wire lies along the y-axis and carries a current I=8A in the y-direction (as shown in Fig) In addition to the magnetic field due to the current in the wire, a uniform magnetic field vecB_0 with magnitude 1.50xx10^-6T is in the +x direction. What is the total field (magnitude and direction ) at following points in the plane? (a) x=0,z=1.00m (b) x=1.00m,z=0 (c) x=0, z=-0.25m