The number of real roots of the equation `4x^(3)-x^(2)+lambda^(2)x-mu=0`, `mu in R, lambda > 1` is

Roots of the equation (x^(2)-4x+3)+lambda(x^(2)-6x+8)=0lambda in R will be

The equation (x^(2)-6x+8)+lambda (x^(2)-4x+3)=0, lambda in R has

Minimum possible number of positive root of the quadratic equation x^(2)-(1+lambda)x+lambda-2=0,lambda in R

If lambda in R is such that the sum of the cubes of the roots of the equation x^(2)+(2-lambda)x+(10-lambda)=0 is minimum then the magnitude of the difference of the roots of this equation is :

The equation x^(2)-6x+8+lambda(x^(2)-4x+3)=0,AA lambda in R-{-1} has

The number of solutions of the equation x^(3)+2x^(2)+5x+2cos x=0 in [0,2 pi] is lambda then (lambda)/(4)=

the equation (x^(2)-6x+8)+lambda(x^(2)-4x+3)=0 for lambda varepsilon R-{-1} has

If the equation x^(2)+lambda x+mu=0 has equal roots and one root of the equation x^(2)+lambda x-12=0 is 2 ,then (lambda,mu) =

If alpha,beta be the roots of the equation 4x^(2)-16x+lambda=0 where lambda in R such that 1

alpha , beta are roots of the equation lambda(x^(2)-x)+x+5=0. If lambda_1 and lambda_2 are the two values of lambda for which the roots alpha , beta are connected b the relation (alpha )/(beta)+(beta)/(alpha)=4 , then the value of (lambda_1)/(lambda_2)+(lambda_2)/(lambda_1) is :