A resistance of R draws current from a potentiometer. The potentiometer wire, AB , has a total resistance of `R_(0)`, A voltage V is supplied to the potentiometer. Derive an expression for the voltage across R when the sliding contact is in the middle of potentialmeter wire.

A constant voltage of 3 V is supplied to a potentiometer wire. A cell of emf 2 V is balanced by a voltage drop across 416 cm of the wire. Find the total length of the potentiometer wire.

AB is wire of potentiometer with the increase in the value of resistance R, the shift in the balance point J will be

The given potentiometer has its wire of resistance 10 Omega When the sliding contact is in the middle of the potentiometer wire, the potential drop across 2 Omega resistor is :

When a balance point is obtained in a potentiometer for finding the internal resistance of a cell, the current through the potentiometer wire is due to

A current of 1.0 mA is flowing through a potentiometer wire of length 4 m and of resistance 4 Omega , find the potential gradient of potentiometer wire

A constant voltage V_0 is applied to a potentiometer of resistance R connected to an ammeter. A constant resistor r is connected to the sliding contact of the potentiometer and the fixed end of the potentiometer. How will the reading of ammeter vary as the sliding contact is moved from one end of the potentiometer to the other ? The resistance of ammeter is assumed to be negligible.

A potentiometer wires has a length L and a resistance R_(0) . It is connected to a battery and a parallel resistance combination of R and S as shown in fogure. Find an exprssion for the potential gradient of the potentiometer wire.

If the potentiometer wire having resistance rho ohm/ m and I amp. current is allowed to pass through it. The potential gradient produced on the potentiometer wire will be