Two satellites A and B of masses 200kg and 400kg are revolving round the earth at height of 600 km and 1600 km respectively. If `T_(A) and T_(B)` are the time periods of A and B respectively then the value of `T_(B)- T_(A)`:

[Given : radius of earth = 6400km, mass of earth = `6xx10^(24)kg]`

Two satellites A and B are revolving around the earth with the same angular speed .If they are at heights of 300 km and 500 km respectively . Then the cenctripetal acceleration will be

Any satellite revolving round the earth in an orbit of height 36000 km with time period of 24 hours

Satellite revolving around the earth at a height of 400 Km above the earth's surface has a time period of about

A and B are two satellite revolving around the earth in circular orbits with radii R_(A) and R_(B) . Their periods T_(A) and T_(B) are 8 h and 1 h respectively. Then the ratio of (R_(A)//R_(B)) is equal to

A satellite is revolving round the earth at a height of 600 km. find a. the speed f the satelite and b. the time period of thesatellit. Radius of the earth =6400 km and mass of the earth =6xx10^24kg .

A satellite of mass 10^(7) kg is revolving around the earth with a time period of 30 days at a height of 1600 km. Find out the force of attraction on satellite by earth?

Satellites A and B are revolving around the earth. The mass of A is 10 times to mass of B. The ratio of time period (T_A/T_B) is x. Find x.

Two satellites of one metric ton and twelve metric tons masses are revolving around the Earth. The heights of these two satellites from the Earth are 1600 km and 25600 km, respectively. What is the ratio of their time periods and what is the ratio of the accelerations due to gravity at those heights? (Radius of the Earth = 6400km)

Find wight of the body of mass 200 kg on the earth at equator and at the latitude of 30^(@) [ Take R= 6400 km]

Determine the binding energy of satellite of mass 1000 kg revolving in a circular orbit around the Earth when it is close to the surface of Earth. Hence find kinetic energy and potential energy of the satellite. [Mass of Earth =6xx10^(24)kg , radius of Earth =6400km , gravitational constant G=6.67xx10^(-11)Nm^(2)//kg^(2) ]