if `x=a(costheta+thetasintheta) , y=a(sintheta-thetacostheta)` then `(d^2y)/(dx^2)`

If x=a(costheta+thetasintheta),y=a(sintheta-thetacostheta)," then "(dy)/(dx)=

Consider the curve x=a(cos theta+thetasintheta) and y=a(sin theta-thetacostheta) . what is (d^(2)y)/(dx^(2)) equal to ?

Consider the curve x=a(cos theta+thetasintheta) and y=a(sin theta-thetacostheta) . What is (dy)/(dx) equal to ?

Find (dy)/(dx) , if x=a(costheta+thetasintheta) , y=a(sintheta-thetacostheta)

If x=ae^(theta)(sintheta-costheta),y=ae^(theta)(sintheta+costheta)," then "((dy)/(dx))" at "theta=(pi)/(2) is

If x=sintheta+thetacostheta,y=costheta-thetasintheta," then "((dy)/(dx))" at "theta=(pi)/(2) is

If x=theta-sintheta" and "y=1-costheta," then "(d^(2)y)/(dx^(2))=

If x= 2 sintheta - sin2theta and y= 2 costheta - cos 2theta then (d^2y)/(dx^2) " at " theta =pi is :

If y=a(theta+sintheta),x=a(1-costheta)," then "(dy)/(dx)=