A particle is performing SHM according to the equation `x=(3cm)sin((2pi)/(18)t+(pi)/(6))`, where t is in seconds. The distance travelled by the particle in 39 s is

A particle is performing SHM according to the equation x=(3cm)sin((2pi)/(18)+(pi)/(6)) , where t is in seconds. The distance travelled by the particle in 39 s is

A particle executes SHM according to equation x=10(cm)cos[2pit+(pi)/(2)] , where t is in seconds. The magnitude of the velocity of the particle at t=(1)/(6)s will be :-

A particles executes SHM according to the equation y = 2 sin 2pit , where y is displacement in m and t is time in s. The distance covered by the particle in 4 s of its motion is

The position of a particle is defined by vec r = 2sin((pi)/(4))t hati + 2cos((pi)/(4))t hatj+3t hatk , where 't' is in seconds. Then distance travelled by particle in 2 second motions is. [use pi^(2) = 10]

x - t equation of a particle in SHM is x = (4 cm)cos ((pi)/(2)t) Here , t is in seconds. Find the distance travelled by the particle in first three seconds.

A particle executes simple harmonic motion according to the displacement equation y = 10 cos(2 pi t + (pi)/(6))cm where t is in second The velocity of the particle at t = 1/6 second will be

A particle is oscillating according to the equation x = 8 cos pi t , where 't' is in second. The particle moves from the position of equilibrium to maximum displacement in time

A particle oscillates with S.H.M. according to the equation x = 10 cos ( 2pit + (pi)/(4)) . Its acceleration at t = 1.5 s is

A particle osciallates with SHM according to the equation x= (2.5 m ) cos [ ( 2pi t ) + (pi)/(4)] . Its speed at t = 1.5 s is

A particle is moving along the x-axis such that s=6t-t^(2) , where s in meters and t is in second. Find the displacement and distance traveled by the particle during time interval t=0 to t=5 s .