`|[0,x-a,x-b],[x+a,0,x-c],[x+b,x+c,0]|=0`

Solve : det[[0,x-a,x-bx+a,0,x-cx+b,x+c,0]]=0

If a ne b ne c , then one value of x which satisfies the equation. [(0,x-a,x-b),(x+a,0,x-c),(x+b,x+c,0)] = 0 is given by :

det[[0,x-a,x-bx+a,0,x-cx+b,x+c,0]]=0

If f(x) = |(0, x-a, x-b),(x+a, 0, x-c),(x+b, x+c, 0)| , then the value of f(0) is :

|[x+a, b, c], [a, x+b, c], [b, b, x+c]|=0

The equation |(x-a,x-b,x-c),(x-b,x-a,x-c),(x-c,x-b,x-a)|=0 (a,b,c are different) is satisfied by (A) x=(a+b+c0 (B) x= 1/3 (a+b+c) (C) x=0 (D) none of these

If a+b+c=0, solve the equation: |[a-x, c, b],[c,b-x, a],[b, a, c-x]|=0

Let matrix M(x) = [(0, (x-a), (x-b)), ((x+a),0,(x-c)),((x+b),(x+c),0)] , then the matrix (M(0)) (M(0))^T (a, b, c !=0) , is (A) null matrix (B) skew-symmetric matrix (C) orthogonal matrix (D) symmetric matrix

If f(x)=|0x-a x-b x+a0x-c x+b x+c0|,t h e n f(x)=0 (b) f(b)=0 (c) f(0)=0 f(1)=0