`A(1,2)`,`B(2,-3)` And `C(-2,3)` are three points. A point P moves such that `PA^(2)+PB^(2)=2PC^(2)`.Show that the equation to the locus of P is `7x-7y+4=0`

A(1, 2) B(2, -3) C(-2, 3) are three points. If P is a point moves such that PA^2 + PB^2 = 2PC^2 then the locus of P is

A(2,3),B(1,5),C(-1,2)" are three points.If "P" is a point moves such that "PA^(2)+PB^(2)=2PC^(2)" ,then the locus of "P" is "

A(2,3) , B(-2,3) are two points.The locus of p which moves such that PA-PB=4 is

A(2,3),B(-2,3) are two points.The locus of P which moves such that PA-PB=4

The coordinates of the point A and B are (a,0) and (-a,0), respectively.If a point P moves so that PA^(2)-PB^(2)=2k^(2), when k is constant,then find the equation to the locus of the point P.

A(-2 3) B(4 -5) are given points.Point P moves such that PA^(2)-PB^(2)=20 .locus of P obtained is ax+by+c=0 then |(a/c)| is

A(2,3),B(2,-3) are two points.The equation to the locus of P. such that PA+PB=8

If A(3,4,1) and B(-1,2,3) are two points, then find the locus of a moving point P such that PA^(2)+PB^(2)=2k^(2) .

A(-2, 2, 3) and B(13, -3, 13) and L is a line through A. Q. A point P moves in the space such that 3PA=2PB , then the locus of P is

If product of slopes of tangents from a point P to x^(2)+y^(2)=a^(2) is 4, then equation of locus of P is