Home
Class 11
CHEMISTRY
Calculate the pH of a buffer solution co...

Calculate the pH of a buffer solution containing 0.15 mole of ` CH_3COOH ` and 0.1 mole of `CH_3 COO Na ` per litre. The dissociation constant for acetic acid ` 1.8 xx 10 ^(-5)`

Text Solution

AI Generated Solution

To calculate the pH of a buffer solution containing acetic acid (CH₃COOH) and sodium acetate (CH₃COONa), we can use the Henderson-Hasselbalch equation. Here are the steps to solve the problem: ### Step 1: Identify the given values - Concentration of acetic acid (CH₃COOH) = 0.15 moles/L - Concentration of sodium acetate (CH₃COONa) = 0.1 moles/L - Dissociation constant (Kₐ) for acetic acid = 1.8 × 10^(-5) ### Step 2: Calculate pKₐ ...
Promotional Banner

Topper's Solved these Questions

  • EQUILIBRIUM

    ICSE|Exercise REVIEW EXERCISES |105 Videos
  • EQUILIBRIUM

    ICSE|Exercise VERY SHORT ANSWER TYPE QUESTIONS |38 Videos
  • ENVIRONMENTAL CHEMISTRY

    ICSE|Exercise NCERT TEXT-BOOK EXERCISE|20 Videos
  • HYDROCARBONS

    ICSE|Exercise NCERT TEXT-BOOK EXERCISES |46 Videos

Similar Questions

Explore conceptually related problems

Calculate the pH of 0.01 M Solution of CH_3 COOH . The dissociation constant of the acid is 1.8 xx 10 ^(-5)

The pH of a buffer solution containing 25 ml of 1 M CH_(3)COONa " and 1 M " CH_(3)COOH will be appreciably affected by

A buffer solution contains 0.15 moles of acetic acid and 0.20 moles of potassium acetate per litre. The dissociation constant of acetic acid at room temperature is 1.76×10^(−5) Calculate the pH of the solution.

The Ph of basic buffer mixtures is given by : Ph=Pk_(a)+ log (["Base"])/(["Salt"]) whereas Ph of acidic buffer mixtures is given by : Ph = pK_(a)+"log"(["Salt"])/(["Acid"]) . Addition of little acid or base although shows no appreciable change in Ph for all practical purposes, but sicne the ratio (["Base"])/(["Salt"]) or (["Salt"])/(["Acid"]) changes, a slight decrease or increase in pH results. Calculate the ratio of pH of a solution containing 1 mole of CH_3COONa + 1 mole of HCl per litre and of other solution containing 1 mole CH_3COONa + 1 mole of acetic acid per litre

Calculate the degree of ionisation and [H_3O^(+) ] of a 0.15 M CH_3COOH solution. The dissociation constant of acetic acid is 1.8 xx 10^(-5)

Calculate the pH of a solution containing 0.1 M CH_(3)COOH and 0.15 M CH_(3)COO^(-) . (K_(a) "of" CH_(3)COOH=1.8xx10^(-5))

Calculate pH of the buffer solution containing 0.15 mole of NH_(4)OH " and " 0.25 mole of NH_(4)Cl. K_(b) " for " NH_(4)OH " is " 1.98 xx 10^(-5) .

Calculate the hydrogen ion concentration ( "in mol"//dm^3 ) in a solution containing 0.04 mole of acetic acid and 0.05 mole of sodium acetate in 500 mL of solution.Dissociation constant for acetic acid is 1.75xx10^(-6) Report your answer after multiplying by 2xx10^(6)

one litre of an aqueous solution contains 0.15 mole of CH_(3)COOH(pK_(a=4.8)) and 0.15 mole of CH_(3) COONa. After the addition of 0.05 mole of solid NaOH to this solution, the pH will be :

A buffer solution contains 0.15 moles of acetic acid and 0.20 moles of potassium acetate per litre. What would be the change in pH of the solution, if 0.5 mL of 1M HCl is added to it? Assume that the volume is unchanged. The dissociation constant of acetic acid at room temperature is 1.76 xx 10^(-5)

ICSE-EQUILIBRIUM -NCERT TEXT-BOOK EXERCISE
  1. Calculate the pH of a buffer solution containing 0.15 mole of CH3COOH...

    Text Solution

    |

  2. A liquid is in equilibrium with its vapour in a seated container at a ...

    Text Solution

    |

  3. A liquid is in equilibrium with its vapour in a seated container at a ...

    Text Solution

    |

  4. A liquid is in equilibrium with its vapour in a seated container at a ...

    Text Solution

    |

  5. What is K(c) for the following equilibrium when the equilibrium concen...

    Text Solution

    |

  6. At a certain temperature and total pressures of 10^(5)Pa, iodine vapou...

    Text Solution

    |

  7. Write the expression for the equilibrium constant, K(c) for each of th...

    Text Solution

    |

  8. Write the expression for the equilibrium constant, K(c) for each of th...

    Text Solution

    |

  9. Write the expression for the equilibrium constant, K(c) for each of th...

    Text Solution

    |

  10. Write the expressions for the equilibrium constant Kc for each of t...

    Text Solution

    |

  11. Write the expressions for the equilibrium constant Kc for each of t...

    Text Solution

    |

  12. Find out of the value of K(c) for each of the following equilibrium fr...

    Text Solution

    |

  13. Find out of the value of K(c) for each of the following equilibrium fr...

    Text Solution

    |

  14. For the following equilibrium K(c) = 6.3 xx 10^(14) at 1000 K NO(g) ...

    Text Solution

    |

  15. Explain why pure liquids and solids can be ignored while writing the e...

    Text Solution

    |

  16. Reaction between N(2) and O(2-) takes place as follows : 2N(2)(g) + ...

    Text Solution

    |

  17. Nitric oxide reacts with Br(2) and gives nitrosul bromide as per react...

    Text Solution

    |

  18. At 450 K, K(p) = 2.0 xx 10^(10)//"bar" for the given reaction at equil...

    Text Solution

    |

  19. A sample of HI(g) is placed in flask at at pressure of 0.2 atm . At eq...

    Text Solution

    |

  20. A mixture of 1.57 mol of N(2), 1.92 mol of H(2) and 8.13 mol of NH(3) ...

    Text Solution

    |

  21. The equilibrium constant expression for a gas reaction is . K(c) = (...

    Text Solution

    |