In which of the following case, does the reaction go farthest to completion ?

Options

A. ` K= 10 ^(2)`
B. ` K= 10 ^(-2)`
C. ` K=10 `
D. ` K= 1 `

Answer

To determine in which case the reaction goes farthest to completion, we need to analyze the given equilibrium constants (K) for each option. The equilibrium constant is a measure of the ratio of the concentrations of products to reactants at equilibrium. A higher value of K indicates that the reaction favors the formation of products, meaning it goes farther to completion.

### Step-by-Step Solution:

1. **Identify the Options:**
- Option 1: K = 10²
- Option 2: K = 10⁻²
- Option 3: K = 10
- Option 4: K = 1

2. **Understand the Significance of K:**
- The equilibrium constant (K) is defined as:
\[ K = \frac{[\text{Products}]}{[\text{Reactants}]} \]
- A higher K value indicates a greater concentration of products at equilibrium, suggesting that the reaction proceeds further toward completion.

3. **Compare the Values of K:**
- Option 1: K = 10² = 100
- Option 2: K = 10⁻² = 0.01
- Option 3: K = 10 = 10
- Option 4: K = 1 = 1

4. **Determine Which K is Highest:**
- Among the options, K = 100 (Option 1) is the highest value.
- The order of K from highest to lowest is:
- Option 1 (K = 100) > Option 3 (K = 10) > Option 4 (K = 1) > Option 2 (K = 0.01)

5. **Conclusion:**
- Since a higher K value indicates that the reaction goes farther to completion, we conclude that the reaction with K = 10² (Option 1) goes farthest to completion.

### Final Answer:
The reaction goes farthest to completion in **Option 1: K = 10²**.

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