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The equilibrium constant for the followi...

The equilibrium constant for the following reaction will be
`P_(4(s))+5O_(2(g))hArrP_(4)O_(10(s))`

A

`K_c= ( [P_4O_(10) ])/([P_4][O_2]^(5)) `

B

` K_c= ( [P_4O_(10) ])/( 5[P_4][O_2]) `

C

` K_c= [O_2]^(5)`

D

` K_c= (1)/([O_2]^(5)) `

Text Solution

Verified by Experts

The correct Answer is:
D
` [P_4 (s) ] =[P_4O_(10 ) (s) ] =1 ` (by convention)
` ([P_4O_(10 ) (s) ])/([P_4 (s) ] [O_2(g) ^(5)] )= (1)/( 1 xx [O_2 (g) ]^(5) ) = ( 1)/([O_2] ^(5)) `
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