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For the reactions, CO(g) +Cl2( g) hA...

For the reactions,
` CO(g) +Cl_2( g) hArr COCl_2(g), " the " (K_P)/(K_c) ` is equal to

A

` (1)/( RT) `

B

RT

C

` sqrt(RT) `

D

` 1.0 `

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The correct Answer is:
To find the relationship between \( K_p \) and \( K_c \) for the reaction: \[ \text{CO(g)} + \text{Cl}_2(g) \rightleftharpoons \text{COCl}_2(g) \] we can follow these steps: ### Step 1: Write the expression for \( K_p \) and \( K_c \) For the reaction, the equilibrium constant in terms of partial pressures (\( K_p \)) and concentrations (\( K_c \)) can be defined as follows: - \( K_p = \frac{P_{\text{COCl}_2}}{P_{\text{CO}} \cdot P_{\text{Cl}_2}} \) - \( K_c = \frac{[COCl_2]}{[CO] \cdot [Cl_2]} \) ### Step 2: Use the relationship between \( K_p \) and \( K_c \) The relationship between \( K_p \) and \( K_c \) is given by the formula: \[ K_p = K_c \cdot (RT)^{\Delta N_g} \] where: - \( R \) is the universal gas constant, - \( T \) is the temperature in Kelvin, - \( \Delta N_g \) is the change in the number of moles of gas. ### Step 3: Calculate \( \Delta N_g \) To find \( \Delta N_g \), we need to determine the change in the number of moles of gaseous products and reactants: - Moles of gaseous products: 1 (from \( \text{COCl}_2 \)) - Moles of gaseous reactants: 2 (1 from \( \text{CO} \) and 1 from \( \text{Cl}_2 \)) Thus, \[ \Delta N_g = \text{(moles of products)} - \text{(moles of reactants)} = 1 - 2 = -1 \] ### Step 4: Substitute \( \Delta N_g \) into the equation Now, substituting \( \Delta N_g \) into the relationship: \[ K_p = K_c \cdot (RT)^{-1} \] ### Step 5: Rearranging for \( \frac{K_p}{K_c} \) To find \( \frac{K_p}{K_c} \): \[ \frac{K_p}{K_c} = \frac{K_c \cdot (RT)^{-1}}{K_c} = \frac{1}{RT} \] ### Final Answer Thus, the relationship between \( K_p \) and \( K_c \) for the given reaction is: \[ \frac{K_p}{K_c} = \frac{1}{RT} \]

To find the relationship between \( K_p \) and \( K_c \) for the reaction: \[ \text{CO(g)} + \text{Cl}_2(g) \rightleftharpoons \text{COCl}_2(g) \] we can follow these steps: ...
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