The equilibrium constant for the reacction `N_(2)(g)+O_(2)(g)hArr2NO(g)` at temperature (T) `4xx10^(-4)` The value of `K_(c)` for the reaction `NO(g)hArr(1)/(2) N_(2)(g)+(1)/(2)O_(2)(g) at the same temperature ?
`(1)/(2)F_(2)(g)hArrF(g)`

Options

A. ` 2.5 xx 10 ^(-2)`
B. ` 50`
C. ` 4 xx 10 ^(-4)`
D. ` 0.02`

Answer

B

Explanation

For the reaction
` 2NO_2 (g) hArr 2NO( g) +O_2 (g)`
` " " Delta n =(2+1) -2=1 `
` K_p =K_c (RT) ^(Delta n ) " " (R = 8.314 JK ^(-) " mol" ^(-1) ) `
` " " = 1.8 xx 10 ^(-6) xx (8.314 xx 457 )^(1) `
` " " = 6. 839 xx 10 ^(-3) J " mol"^(-1) `
` therefore K_b gt K_c `