If a solution has of a pOH value of 14 at ` 25^(@)C , H^(+) ` ion concentration in mol `L^(-1)` should be

Options

A. `0`
B. ` 1`
C. ` 10 `
D. ` 14`

Explanation

To find the concentration of \( H^+ \) ions in a solution with a pOH value of 14 at \( 25^\circ C \), we can follow these steps:

### Step-by-Step Solution:

1. **Understand the relationship between pH and pOH**:
At \( 25^\circ C \), the relationship between pH and pOH is given by the equation:
\[ \text{pH} + \text{pOH} = 14 \]

2. **Substitute the given pOH value**:
We know that the pOH is 14. Therefore, we can substitute this value into the equation:
\[ \text{pH} + 14 = 14 \]

3. **Solve for pH**:
Rearranging the equation gives us:
\[ \text{pH} = 14 - 14 = 0 \]

4. **Use the pH to find the concentration of \( H^+ \)**:
The concentration of \( H^+ \) ions is related to pH by the formula:
\[ \text{pH} = -\log[H^+] \]
Substituting our value of pH:
\[ 0 = -\log[H^+] \]

5. **Convert the logarithmic equation to exponential form**:
To remove the logarithm, we can rewrite the equation:
\[ [H^+] = 10^{0} \]

6. **Calculate the concentration**:
Since \( 10^{0} = 1 \), we find:
\[ [H^+] = 1 \, \text{mol/L} \]

### Final Answer:
The concentration of \( H^+ \) ions in the solution is \( 1.0 \, \text{mol/L} \).

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