According to Henderson's equation,
` pOH = -log_(10) ……..+ log_(10) (["Salt"])/([………]) `

Explanation

To solve the question regarding Henderson's equation for pOH, we will follow these steps:

### Step-by-Step Solution:

1. **Understanding the Base Dissociation**:
We start with the dissociation of a base \( B \) in water:
\[
B + H_2O \rightleftharpoons OH^- + BH^+
...