Find out of the value of `K_(c)` for each of the following equilibrium from the value of `K_(p)`:
(i) `2NOCl (g) hArr 2NO(g) + Cl_(2)(g), K_(p) = 1.8 xx 10^(-2)` at `500 K`
(ii) `CaCO_(3) (s) hArr CaO(s) + CO_(2)(g), K_(p) = 167` at `1073 K`

Explanation

For the reaction ,
` CaCO_3 hArr CaO(s) + CO_2 (g) , Delta n= 1 - 0=1 `
` because K_c= (K_P) /((RT)^(Delta n )) = (167)/((0.0831 xx 1073)) = 1.873`