A sample of `HI(g)` is placed in flask at at pressure of `0.2` atm . At equilibrium the partial pressure of `HI(g)` is `0.04 `atm what is `K_(p)` for the given equilibrium ?
`2HI(g) hArr H_(2)(g) + I_(2)(g)`

Explanation

` {:(,2Hl(g) , hArr ,H_2(g) , +,I_2(g)) ,( "Initial pressure " , 0.2 " atm " , , -, ,- ),(" pressure at equilibrium ",0.04 "atm " ,, (0.2- 0.4)/(2),,(0.2 - 0. 4 )/(2)):}`
` [because (0.2 - 0.04 ) ` is the decrease in the pressure of Hl]
` K_p = (rho _(H_2)xx rho _(I_2))/(rho_(Hl)^(2))= (0.08 xx 0.08 )/((0.04)^(2)) = 4.0 `