Ethyl acetate is formed by the reaction between ethanol and acetic acid and the equilibrium is represented as :
` CH_3COOH(l) +C_2H_5OH(l) hArr CH_3COOC_2H_5(l) +H_2O(l)`
Starting with 0.5 mol of ethanol and 1.0 mol of acetic acid and maintaining it at 293 K, 0.214 mol of ethyl acetate is found after sometime . Has equilibrium been reached?

Explanation

To determine if equilibrium has been reached in the reaction between ethanol and acetic acid to form ethyl acetate and water, we can follow these steps:

### Step 1: Write the balanced chemical equation
The reaction is given as:
\[ \text{CH}_3\text{COOH (l)} + \text{C}_2\text{H}_5\text{OH (l)} \rightleftharpoons \text{CH}_3\text{COOC}_2\text{H}_5 (l) + \text{H}_2\text{O (l)} \]

### Step 2: Identify initial concentrations
From the problem, we have:
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