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At 473K, equilibrium constant, K(c) for ...

At 473K, equilibrium constant, `K_(c)` for decomposition of phosphorus pentachloride, `PCl_(5)` is `8.3xx10^(-3)`. If decomposition is depicted as :
`PCl_(5(g))hArrPCl_(3(g))+Cl_(2(g)),Delta_(r)H^(@)=124.0" kJ mol"^(-1)`
what would be the effect on reaction if the temperature is increased ?

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Verified by Experts

` K. = (1)/(K_C) = (1)/(8.3 xx10 ^(-3)) = 120 .48`
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At 473 K , equilibrium constant K_(c ) for decomposition of phosphorus pentachloride, PCl_(5) is 8.3xx10^(-3) . If decomposition is depicted as, PCl_(5)(g) hArr PCl_(3)(g)+Cl_(2)(g) Delta_(r)H^(Θ)=124.0 kJ mol^(-1) a. Write an expression for K_(c ) for the reaction. b. What is the value of K_(c ) for the reverse reaction at the same temperature? c. What would be the effect on K_(c ) if i. More PCl_(5) is added ii. Pressure is increased iii. The temperature is increased?

For the reaction : PCl_(5) (g) rarrPCl_(3) (g) +Cl_(2)(g) :

For the reaction : PCl_(5) (g) rarrPCl_(3) (g) +Cl_(2)(g) :

For the reaction PCl_(5)(g) rightarrow PCl_(3)(g) + Cl_(2)(g)

For the gas-phase decomposition, PCl_(5)(g)LeftrightarrowPCl_(3)(g)+Cl_(2)(g)

PCl_(5) is 10% dissociated at 1 atm. What is % dissociation at 4 atm . PCl_(5)(g)hArr PCl_(3)(g)+Cl_(2)(g)

At 473 K, K_(c) for the reaction PCl_(5(g))hArrPCl_(3(g))Cl_(2(g)) is 8.3xx10^(-3) . What will be the value of K_(c) for the formation of PCl_(5) at the same temperature ?

At 473 K, K_(c) for the reaction PCl_(5(g))rArrPCl_(3(g))Cl_(2(g)) is 8.3xx10^(-3) . What will be the value of K_(c) for the formation of PCl_(5) at the same temperature ?

For PCl_(5)(g)hArrPCl_(3)(g)+Cl_(2)(g), write the expression of K_(c)

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