The value of `K_(c)` for the reaction `3O_(2)(g) hArr 2O_(2)(g)` is `2.0 xx 10^(-50)` at `25^(@)C` . If the equilibrium concentration of `O_(2)` in air at `25^(@)C` is `1.6 xx 10^(-2)`, what is the concentration of `O_(3)`?

Explanation

` " " K_c = ([O_3(g)]^(2))/([O_2(g)]^(3))`
`or " " 2.0 xx 10^(-50) =([O_3(g)]^(2))/((1.6 xx 10 ^(-2) ) ^(3))`
` or " " [O_3(g)]^(2) =2.0 xx 10 ^(-50) xx (1.6xx 10 ^(-2))^(3)`
` " " = 8.192 xx 10 ^(-56)`
` therefore " " [O_3 (g) ]=(8.192 xx 10^(-56)) ^(1//2)`
`" " = 2.86 xx 10 ^(-28) M.`