Assuming complete dissociation, calculate the pH of the following solutions:
(a) 0.003 M HCl , (b) 0.005 M NaOH , (c) 0.002 M HBr , (d) 0.002 M KOH

Explanation

` [H_3O]^(+) =[HBr]=0.002 " mol " L^(-1)`
` therefore " " pH= -log_(10) [H_3O^(+) ] =-log _(10) (0.002 )= 2.70 `