Write the IUPAC name of the following compound:
`CH_3 - overset(O) overset(||)C-overset(CH_3)overset(|)(CH )- underset(C_2 H_5) underset(|)overset(Cl ) overset(| )C-overset(CH_3) overset(|) (CH )- overset(NO_2)overset(|)(CH) -underset(C_2 H_5) underset(|)(CH) - CH_3`

Explanation

The given compound can be written as
`overset(1)CH_3 - overset(O ) overset(||)C - overset(CH_3)overset(3|)(CH )- underset(C_2 H_5) underset(|)overset(Cl) overset(4|)C-overset(CH_3) overset(5|) (CH ) - overset(NO_2) overset(6|)(CH ) -underset(""^8 CH_2 - overset(9)(CH_3))underset(|) overset(7)(CH ) -CH_3`
(i) The principal group is `-overset(O )overset(।। )C-` as it ranks higher than `-NO_2` and —Cl groups in the seniority table.
(ii) The numbering should be done from the left.
(iii) The parent hydrocarbon is nonane and the word root is non.
(iv) The primary suffix is ane (as the chain is saturated), while the secondary suffix is one.
(v) Adding primary suffix ane (e will be dropped),secondary suffix - one (corresponding to `gt CO` group at position 2) and prefixes chloro (corresponding to -Cl group at position 4) and nitro- (corresponding to -NO2 group at position 6) to the word root and mentioning their positions, we get 4-chloro-6-nitrononan-2one.
(vi) The compound contains one ethyl group at position 4 and three methyl groups at positions 3, 5 and 7. Therefore, the complete IUPAC name of the compound would be 4-chloro-4-ethyl-3, 5, 7-trimethyl-6 nitrononan-2-one.