In the steam distillation of an organic oil (immiscible with water), the mixture of oil and water boils at 372 K under 1 atm pressure. The vapour pressure of water is 595 mm of Hg at this temperature. The collected condensate contains 50% by weight of the oil. Calculate the molecular weight of the oil.

Explanation

To find the molecular weight of the organic oil in the steam distillation process, we will follow these steps:

### Step 1: Understand the given data
- The boiling point of the mixture is 372 K.
- The total pressure of the mixture is 1 atm, which is equivalent to 760 mm Hg.
- The vapor pressure of water at this temperature is 595 mm Hg.
- The collected condensate contains 50% by weight of the oil.

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