A dihaloalkane (A), `C_2 H_8 Cl_2` on reaction with alc. KOH gives (B), `C_6 H_6.` (B) does not form white precipitate with ammonical silver nitrate and on hydrogenation absorbs two moles of hydrogen to give n-butane. Compound (B) reacts with two molecules of ozone to form a diozonide which on reductive hydrolysis gives two moles of formaldehyde and one mole of glyoxal. Identify (A) and (B) and explain the reactions.

Explanation

To solve the problem, we need to identify the compounds (A) and (B) based on the given information and reactions. Let's break it down step by step.

### Step 1: Identify Compound A
The molecular formula for compound A is given as `C2H8Cl2`. This indicates that it is a dihaloalkane.

- The presence of two chlorine atoms suggests that it can be a 1,4-dichlorobutane, which can be represented as:
\[
\text{CH}_2\text{Cl}-\text{CH}_2-\text{CH}_2-\text{CH}_2\text{Cl}
...