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Following types of compounds (as I, II) ...

Following types of compounds (as I, II)
`(I) CH_3 CH = CHCH_3`
`(II) CH_3 - underset(CH_2 CH_3)underset(|) CH -OH `
are studied in terms of isomerism in

A

chain isomerism

B

position isomerism

C

conformers

D

stereo isomerism.

Text Solution

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The correct Answer is:
To solve the question regarding the types of isomerism exhibited by the given compounds (I) and (II), we will analyze each compound step by step. ### Step 1: Analyze Compound I (CH₃CH=CHCH₃) 1. **Identify the structure**: The compound CH₃CH=CHCH₃ has a carbon-carbon double bond between the second and third carbon atoms. 2. **Determine the presence of different groups**: Each carbon involved in the double bond has different substituents: - The second carbon (C2) has a methyl group (CH₃) and a hydrogen (H). - The third carbon (C3) has a methyl group (CH₃) and a hydrogen (H). 3. **Check for restricted rotation**: The double bond restricts rotation, allowing for the possibility of geometric isomers (cis and trans forms). 4. **Conclusion**: This compound can exhibit **geometric isomerism** (cis-trans isomerism). ### Step 2: Analyze Compound II (CH₃-CH₂-CH(OH)-CH₃) 1. **Identify the structure**: The compound CH₃-CH₂-CH(OH)-CH₃ has a hydroxyl (-OH) group attached to the third carbon. 2. **Determine chirality**: The carbon that is attached to the -OH group (C3) is connected to four different groups: - A methyl group (CH₃) - An ethyl group (CH₂CH₃) - A hydrogen (H) - A hydroxyl group (OH) 3. **Check for symmetry**: Since C3 is attached to four different groups, it is a chiral center. There are no symmetry elements (like a plane of symmetry) present in this compound. 4. **Conclusion**: This compound can exhibit **optical isomerism** due to the presence of a chiral center. ### Step 3: Combine the Findings 1. **Identify the types of isomerism**: - Compound I shows **geometric isomerism**. - Compound II shows **optical isomerism**. 2. **Categorize the isomerism**: Both types of isomerism fall under the broader category of **stereoisomerism**. ### Final Conclusion Both compounds (I) and (II) are studied in terms of **stereoisomerism**, which includes both geometric and optical isomerism. ---

To solve the question regarding the types of isomerism exhibited by the given compounds (I) and (II), we will analyze each compound step by step. ### Step 1: Analyze Compound I (CH₃CH=CHCH₃) 1. **Identify the structure**: The compound CH₃CH=CHCH₃ has a carbon-carbon double bond between the second and third carbon atoms. 2. **Determine the presence of different groups**: Each carbon involved in the double bond has different substituents: - The second carbon (C2) has a methyl group (CH₃) and a hydrogen (H). - The third carbon (C3) has a methyl group (CH₃) and a hydrogen (H). 3. **Check for restricted rotation**: The double bond restricts rotation, allowing for the possibility of geometric isomers (cis and trans forms). ...
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