Of the five isomeric hexanes, the isomer which can give two monochlorinated compounds is
2-methylpentane
2,2-dimethylbutane
2,3-dimethylbutane
n-hexane.

Options

A. 2-methylpentane
B. 2,2-dimethylbutane
C. 2,3-dimethylbutane
D. n-hexane.

Explanation

To solve the question of which isomeric hexane can give two monochlorinated compounds, we need to analyze each of the given options based on their structure and the types of hydrogen atoms they contain.

### Step-by-Step Solution:

1. **Understand the Requirement for Monochlorination**:
- For a compound to yield two different monochlorinated products, it must have at least two types of hydrogen atoms. This means there should be a set of hydrogen atoms that are identical (let's say 4 of them) and another set that is different (let's say 2 of them).

2. **Analyze Each Isomer**:
- **Option 1: 2-Methylpentane**
Structure:
```
CH3
|
CH3-CH-CH2-CH3
|
CH2
```
- In this structure, there are not enough types of hydrogen atoms to yield two different monochlorinated products. Thus, it does not satisfy the requirement.

- **Option 2: 2,2-Dimethylbutane**
Structure:
```
CH3
|
CH3-C-CH2-CH3
|
CH3
```
- This structure also does not provide the necessary variety of hydrogen atoms. All the methyl groups are identical, and thus it cannot yield two different monochlorinated products.

- **Option 3: 2,3-Dimethylbutane**
Structure:
```
CH3
|
CH3-C-CH-CH3
|
CH3
```
- In this case, the hydrogen atoms on the two methyl groups (attached to the second and third carbon) are different from the hydrogen atoms on the other carbons. This structure has 4 identical hydrogen atoms (from the two methyl groups) and 2 different hydrogen atoms (from the other two carbons). Therefore, it can yield two different monochlorinated products.

- **Option 4: n-Hexane**
Structure:
```
CH3-CH2-CH2-CH2-CH2-CH3
```
- This is a straight-chain alkane with no branching. All hydrogen atoms are identical, meaning it cannot produce two different monochlorinated products.

3. **Conclusion**:
- The isomer that can give two monochlorinated compounds is **2,3-Dimethylbutane**.

### Final Answer:
**2,3-Dimethylbutane**