Home
Class 11
CHEMISTRY
The concentration of C = 85.45%, and H =...

The concentration of C = 85.45%, and H = 14.44% is not obeyed by the formula

A

`CH_2`

B

`C_2 H_4`

C

`C_2 H_6`

D

`C_4 H_8`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem regarding the concentrations of carbon and hydrogen, we will follow these steps: ### Step 1: Determine the mass percentages of carbon and hydrogen Given: - Percentage of Carbon (C) = 85.45% - Percentage of Hydrogen (H) = 14.44% ### Step 2: Convert the percentages to grams Assuming we have 100 grams of the compound: - Mass of Carbon = 85.45 g - Mass of Hydrogen = 14.44 g ### Step 3: Calculate the number of moles of each element To find the number of moles, we will use the formula: \[ \text{Number of moles} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}} \] - Molar mass of Carbon (C) = 12 g/mol - Molar mass of Hydrogen (H) = 1 g/mol Calculating the moles: - Moles of Carbon = \(\frac{85.45 \text{ g}}{12 \text{ g/mol}} = 7.12 \text{ moles}\) - Moles of Hydrogen = \(\frac{14.44 \text{ g}}{1 \text{ g/mol}} = 14.44 \text{ moles}\) ### Step 4: Find the simplest ratio of moles To find the simplest ratio, we divide the number of moles of each element by the smallest number of moles calculated: - Ratio of Carbon to Hydrogen = \( \frac{7.12}{7.12} : \frac{14.44}{7.12} = 1 : 2 \) ### Step 5: Write the empirical formula From the ratio of 1:2, the empirical formula is: \[ \text{Empirical Formula} = CH_2 \] ### Step 6: Identify possible molecular formulas The molecular formula can be a multiple of the empirical formula. Possible molecular formulas include: - \(C_2H_4\) (2 times the empirical formula) - \(C_4H_8\) (4 times the empirical formula) ### Step 7: Identify the formula that does not match The question states that the given concentrations do not obey a certain formula. Among the options, \(C_2H_6\) does not match the calculated ratios and is therefore excluded. ### Final Answer: The empirical formula is \(CH_2\) and the molecular formulas \(C_2H_4\) and \(C_4H_8\) are valid, while \(C_2H_6\) does not obey the given concentrations. ---

To solve the problem regarding the concentrations of carbon and hydrogen, we will follow these steps: ### Step 1: Determine the mass percentages of carbon and hydrogen Given: - Percentage of Carbon (C) = 85.45% - Percentage of Hydrogen (H) = 14.44% ### Step 2: Convert the percentages to grams ...
Promotional Banner

Topper's Solved these Questions

  • ORGANIC CHEMISTRY : SOME BASIC PRINCIPLES AND TECHNIQUES

    ICSE|Exercise TRUE OR FALSE TYPE QUESTIONS|50 Videos
  • ORGANIC CHEMISTRY : SOME BASIC PRINCIPLES AND TECHNIQUES

    ICSE|Exercise FILL IN THE BLANK TYPE QUESTIONS |46 Videos
  • ORGANIC CHEMISTRY : SOME BASIC PRINCIPLES AND TECHNIQUES

    ICSE|Exercise ESSAY ( LONG ANSWER ) TYPE QUESTIONS|42 Videos
  • HYDROGEN

    ICSE|Exercise NCERT TEXT-BOOK EXERCISE (With Hints and Solutions)|53 Videos
  • REDOX REACTIONS (OXIDATION AND REDUCTION)

    ICSE|Exercise NCERT TEXT-BOOK. EXERCISES ((With Hints and Solutions)|69 Videos

Similar Questions

Explore conceptually related problems

An organic compound with vapour density = 94 contains C=12.67%, H = 2.13%, and Br = 85-11%. Find the molecular formula. [Atomic mass: C = 12, H = 1, Br = 80]

An organic compound with vapour density 94 contains C = 12.67%, H = 2.13% and Br = 85.20%. Find the molecular formula. (Atomic mass: C = 12, H = 1, Br = 80)

An organic compound is found to contain C - 40%. 0 = 53.34% and H = 6.66%. Its empirical formula is

A compound contains C=40%,O=53.5% , and H=6.5% the empirical formula formula of the compound is:

An organic compound with C =40 % and H= 6.7% will have the empirical formula

An organic compound contains C = 40%, H = 13.33% , and N = 46.67% . Its empirical formula will be

An organic compound containes C=74.0%, H=8.65% and N=17.3% . Its empirical formul ais

Determine the empirical formula of a compound containing Nitrogen = 87.5% and Hydrogen = 12.5%. If the molecular mass is 32. Find its molecular formula.

A primary alcohol (A) with V.D. = 29 contains C = 62.1%, H = 10.3%. It reacts with bromine to form a derivative (B) which contains C = 16.5%, H = 2.7% and Br = 73.4%. Identify (A) and (B).

An inorganic substance has the following composition: N = 35% H = 5%, O = 60 % On being heated, it yielded a gaseous compound containing N = 63.63% and O = 36.37% . Suggest a formula for each substance and equation for the chemical change.

ICSE-ORGANIC CHEMISTRY : SOME BASIC PRINCIPLES AND TECHNIQUES -OBJECTIVE ( MULTIPLE CHOICE ) TYPE QUESTIONS
  1. An organic compound has an empirical formula CH2 O. Its vapour density...

    Text Solution

    |

  2. The empirical formula of a compound is CH2. One mole of this compound ...

    Text Solution

    |

  3. The concentration of C = 85.45%, and H = 14.44% is not obeyed by the f...

    Text Solution

    |

  4. If two compounds have the same empirical formula but different molecul...

    Text Solution

    |

  5. 0.759 g of a silver salt of a dibasic organic acid on ignition gave 0....

    Text Solution

    |

  6. 0.400 g of chloroplatinate salt of a monoacid base on ignition gave 0....

    Text Solution

    |

  7. 0.500 g of the silver salt of an organic dibasic acid on ignition give...

    Text Solution

    |

  8. In a Victor Meyer's determination of molecular mass, 0.1015 g of an or...

    Text Solution

    |

  9. 0.29 g of an organic compound on combustion gave 0.66 g of CO2 and 0.2...

    Text Solution

    |

  10. The blue compound formed in the positive test for nitrogen with Lassai...

    Text Solution

    |

  11. The ammonia evolved from the treatment of 0.30 g of an organic compoun...

    Text Solution

    |

  12. An organic compound having molecular mass 60 is found to contain C = 2...

    Text Solution

    |

  13. The blue compound formed in the positive test for nitrogen with Lassai...

    Text Solution

    |

  14. 29.5 mg of an organic compound containing nitrogen was digested accord...

    Text Solution

    |

  15. In Dumas’ method for estimation of nitrogen, 0.3g of an organic compou...

    Text Solution

    |

  16. For testing halogens in an organic compound with AgNO(3) solution, sod...

    Text Solution

    |

  17. In the Kjeldahl's method for estimation of nitrogen present in a soil ...

    Text Solution

    |

  18. For the estimation of nitrogen 1.4 g of organic compound was diagest b...

    Text Solution

    |

  19. Which of the following ions is most stable ?

    Text Solution

    |

  20. The number of electrons present in the valence shell of carbon bearing...

    Text Solution

    |