In a Victor Meyer's determination of molecular mass, 0.1015 g of an organic substance displaced 26.16 mL of air at S.T.P. The molecular mass of the substance is

Options

A. `22.4`
B. `44.8`
C. `76.4`
D. `86.9`

Explanation

To determine the molecular mass of the organic substance using the Victor Meyer method, we can follow these steps:

### Step 1: Understand the formula
The formula to calculate the molecular mass (M) of the organic compound using the Victor Meyer method is:

\[ M = \frac{\text{Weight of organic compound} \times 22400 \, \text{mL}}{\text{Volume of air displaced at STP}} \]

### Step 2: Identify the given values
From the question, we have:
- Weight of the organic compound = 0.1015 g
- Volume of air displaced at STP = 26.16 mL

### Step 3: Substitute the values into the formula
Now we can substitute the values into the formula:

\[ M = \frac{0.1015 \, \text{g} \times 22400 \, \text{mL}}{26.16 \, \text{mL}} \]

### Step 4: Calculate the numerator
First, calculate the numerator:

\[ 0.1015 \, \text{g} \times 22400 \, \text{mL} = 2273.6 \, \text{g mL} \]

### Step 5: Divide by the volume of air displaced
Now, divide the result by the volume of air displaced:

\[ M = \frac{2273.6 \, \text{g mL}}{26.16 \, \text{mL}} \approx 86.9 \, \text{g/mol} \]

### Step 6: Conclusion
The molecular mass of the organic substance is approximately 86.9 g/mol.

### Final Answer
The molecular mass of the substance is **86.9 g/mol**.

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