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Nitration of benzene is...

Nitration of benzene is

A

nucleophilic substitution

B

nucleophilic addition

C

electrophilic substitution

D

free radical substitution.

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The correct Answer is:
To solve the question regarding the nitration of benzene, we will follow a step-by-step approach to understand the mechanism and identify the correct answer from the given options. ### Step 1: Understand the Reaction Nitration of benzene involves the introduction of a nitro group (NO2) into the benzene ring. The reaction is typically carried out using a nitrating mixture of concentrated nitric acid (HNO3) and concentrated sulfuric acid (H2SO4). ### Step 2: Identify the Mechanism The key to determining the type of reaction is to identify the mechanism involved. The options provided are: - Nucleophilic substitution - Nucleophilic addition - Electrophilic substitution - Free radical substitution ### Step 3: Formation of the Electrophile In the nitration process, the first step is the formation of the nitronium ion (NO2+), which acts as the electrophile. This is formed from the reaction of nitric acid and sulfuric acid: - HNO3 + H2SO4 → NO2+ + HSO4- + H2O The nitronium ion is electron-deficient and is capable of attacking the electron-rich benzene ring. ### Step 4: Electrophilic Attack The nitronium ion (NO2+) attacks the benzene ring. The π electrons of the benzene ring react with the nitronium ion, leading to the formation of a carbocation intermediate known as the sigma complex or arenium ion. ### Step 5: Deprotonation In the final step, the carbocation loses a proton (H+) to restore the aromaticity of the benzene ring. The proton is abstracted by the bisulfate ion (HSO4-) formed earlier in the reaction, resulting in the formation of nitrobenzene (C6H5NO2) and regenerating sulfuric acid (H2SO4). ### Conclusion Since the reaction involves the substitution of a hydrogen atom in the benzene ring by a nitro group, and the mechanism involves an electrophile attacking the benzene, the correct answer to the question "Nitration of benzene is" is: **Electrophilic substitution (Option C)**. ---

To solve the question regarding the nitration of benzene, we will follow a step-by-step approach to understand the mechanism and identify the correct answer from the given options. ### Step 1: Understand the Reaction Nitration of benzene involves the introduction of a nitro group (NO2) into the benzene ring. The reaction is typically carried out using a nitrating mixture of concentrated nitric acid (HNO3) and concentrated sulfuric acid (H2SO4). ### Step 2: Identify the Mechanism The key to determining the type of reaction is to identify the mechanism involved. The options provided are: - Nucleophilic substitution ...
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ICSE-ORGANIC CHEMISTRY : SOME BASIC PRINCIPLES AND TECHNIQUES -OBJECTIVE ( MULTIPLE CHOICE ) TYPE QUESTIONS
  1. The compound which gives the most stable carbonium ion on dehydration ...

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  2. In a free radical, the carbon atom carrying unpaired electron is

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  3. Nitration of benzene is

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  4. The reaction intermediates involved in the addition of HBr to propene ...

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  5. The shape of carbanion [CH(3)]^(-) is: linear bent pyramidal ...

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  6. Which of the following is an electrophile ? NH3 AlCl3 OH^(-) CH3-O...

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  7. Heterolytic fission of C—Cl bond produces two free radicals two ca...

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  8. Which one of the following is the strongest acid ?

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  9. The most stable free radical is

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  10. The formation of cyanohydrin from a ketone is an example of nucleophi...

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  11. Which of the following alkyl halides is hydrolysed by S(N^1)mechanism ...

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  12. Which of the following does contain three pairs of electrons ?

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  13. Amongst the following, which are true for S(N^2) reaction ? (i) The ra...

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  14. Nucleophiles are while electrophiles are .

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  15. The + l-effect is shown by

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  16. Wilkinson's catalyst is

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  17. The hardness of water is estimated by (a)conductivity method (b)EDT...

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  18. Which of the following is an organometallic compound ?

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  19. Which of the following is an organometallic compound ?

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  20. In the compound, lithium tetrahydroaluminate, the ligand is

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