Energy of an electron in the ground state of the hydrogen atom is `-2.18xx10(-18)J`. Calculate the ionization enthalpy of atomic hydrogen in terms of J `"mol"^(-1)`.
Hint: Apply the idea of mole concept to derive the answer.

Explanation

The energy required to remove an electron in the ground state of hydrogen atom
`=E_(oo)-E_(1)`
`=0-(-2.18xx10^(-18))`
`=2.18xx10^(-18)J"atom"^(-1)`
`therefore` Ionisation enthalpy of atomic hydrogen
`=2.18xx10^(-18)xx6.022xx10^(23)J"mol"^(-1)`
`=1.313xx10^(6)Jmol^(-1)`