Assign the position of the element having outer electronic configuration `(n - 2) f^(7) (n - 1) d^(1) ns` for n = 6, in the periodic table.

Explanation

To assign the position of the element with the outer electronic configuration `(n - 2) f^(7) (n - 1) d^(1) ns` for n = 6, we can follow these steps:

### Step 1: Determine the values of n
Given that n = 6, we can substitute this value into the outer electronic configuration:
- `(n - 2) = 6 - 2 = 4`
- `(n - 1) = 6 - 1 = 5`

### Step 2: Write the complete outer electronic configuration
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