Calculate the standard enthalpy change for the reaction
`CH_4 (g) + 2O_2(g) to CO_2(g) + 2H_2O(l)`,
given that the standard heatds of formation of `CH_4(g, CO_2(g) and H_2O (l) ` are` -74.91 mol^(-1), -394.12 kJ mol^(-1) and -286.31 kJ mol^(-1)` respectivley.

Explanation

To calculate the standard enthalpy change for the reaction:

\[ \text{CH}_4(g) + 2 \text{O}_2(g) \rightarrow \text{CO}_2(g) + 2 \text{H}_2\text{O}(l) \]

we will use the standard heats of formation provided:

- \(\Delta H_f^\circ (\text{CH}_4(g)) = -74.91 \, \text{kJ/mol}\)
- \(\Delta H_f^\circ (\text{CO}_2(g)) = -394.12 \, \text{kJ/mol}\)
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