Calculate the enthalpy of the following reaction :
`CH_2= CH_2 (g) + H_2(g) to CH_3 - CH_3(g)`
The bond energies of C-H, C-C, C=C and H-H bonds are 414, 347, 615 and 435 kJ `mol^(-1)` respectively.

Explanation

To calculate the enthalpy of the reaction \( CH_2=CH_2(g) + H_2(g) \rightarrow CH_3-CH_3(g) \), we will use the bond energies provided for the different bonds involved in the reaction.

### Step-by-Step Solution:

1. **Identify the Bonds in Reactants:**
- In ethylene (\( CH_2=CH_2 \)):
- There is one C=C double bond.
- There are four C-H bonds (two CH2 groups).
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