For a reaction, `K = 1.958 xx 10^(-4)` at 400 K, what is the value of `DeltaG^@`at this temepratuure ?`(R = 8.314 J K^(-1) mol^(-1))`.

Explanation

To find the value of \( \Delta G^\circ \) at a temperature of 400 K for the given equilibrium constant \( K = 1.958 \times 10^{-4} \), we can use the following equation:

\[ \Delta G^\circ = -2.303 \times R \times T \times \log K \]

Where:
- \( R = 8.314 \, \text{J K}^{-1} \text{mol}^{-1} \)
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