Calculate the equilibrium constant for the following reaction at 298 K and 1 atm pressure.C(graphite)+H2O(l)=CO(g)+H2(g)
Given : 'Delta_f H^@ , [H_2O (l)] = -286.0 kJ mol^(-1)`, `Delta_f H^@ [ CO (g)] = - 110.5 kJ mol^(-1)` , `DeltaS^@` at 298 K for the reaction =252.6 J k^(-1) mol^(-1)`. Gas constant `R = 8.31 Jk^(-1) mol^(-1)`.

Explanation

To calculate the equilibrium constant \( K \) for the reaction

\[ C(\text{graphite}) + H_2O(l) \rightleftharpoons CO(g) + H_2(g) \]

at 298 K and 1 atm pressure, we will follow these steps:

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