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Calculate the entropy change when 20.0 g...

Calculate the entropy change when 20.0 g of ice changes to liquid water at 0°C. The heat of fusion is `80.0 cal g^(-1)`.

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To calculate the entropy change when 20.0 g of ice changes to liquid water at 0°C, we can follow these steps: ### Step 1: Understand the formula for entropy change The change in entropy (ΔS) can be calculated using the formula: \[ \Delta S = \frac{Q}{T} \] where: ...
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Steam at 100°C is passed into 100 g of ice at 0°C . Finally when 80g ice melts the mass of water present will be [Latent heat of fusion and vaporazisation are 80 cal g^(-1) and 540 cal g^(-1) respectively, specific heat of water = 1 cal g^(-1) °C^(-1) ]

A cube of ice of mass 30 g at 0^@ C is added into 200 g of water at 30^@ C. Calculate the final temperature of water when whole of the ice cube has melted. Given: specific latent heat of ice = 80 cal g^(-1) , specific heat capacity of water = 1 cal g^(-1)^@C^(-1)

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