For a hypothetical reaction `nX to mY`, the value of `DeltaH =-133 kJ and DeltaS = -145 J K^(-1)`. Calcualte value of `DeltaS_("surr".) and DeltaS_("univ")`

Explanation

To solve the problem, we need to calculate the change in entropy of the surroundings (\( \Delta S_{\text{surr}} \)) and the change in entropy of the universe (\( \Delta S_{\text{univ}} \)) for the given reaction \( nX \to mY \) with the provided values of \( \Delta H \) and \( \Delta S \).

### Step 1: Calculate \( \Delta S_{\text{surr}} \)

The change in entropy of the surroundings can be calculated using the formula:

\[
\Delta S_{\text{surr}} = -\frac{\Delta H}{T}
...