The reaction
`CH_3COOH(l) + C_2H_5OH(l) hArr CH_3 COOC_2H_5(l) + H_2O (l)`
was carried out at 27°C by taking one mole each of the reactants. The reaction reached equilibrium when 2/3rd of the reactants were consumed. Calculate the free energy change for the reaction.

Explanation

To calculate the free energy change (ΔG) for the reaction

\[ \text{CH}_3\text{COOH}(l) + \text{C}_2\text{H}_5\text{OH}(l) \rightleftharpoons \text{CH}_3\text{COOC}_2\text{H}_5(l) + \text{H}_2\text{O}(l) \]

at 27°C (300 K) when 2/3 of the reactants are consumed, follow these steps:

### Step 1: Determine the initial and equilibrium concentrations
Initially, we have:
...