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H2(g) + 1/2 O2(g) to H2O (l), DeltaH = ...

`H_2(g) + 1/2 O_2(g) to H_2O (l), DeltaH = - 286 kJ`
`2H_2(g) + O_2(g) to 2H_2O (l), DeltaH = …kJ`

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AI Generated Solution

To solve the problem, we need to find the enthalpy change (ΔH) for the reaction: \[ 2H_2(g) + O_2(g) \rightarrow 2H_2O(l) \] We know from the given information that for the reaction: \[ H_2(g) + \frac{1}{2} O_2(g) \rightarrow H_2O(l) \] ...
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