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N2(g) + 3H2(g) to 2NH3(g) , DeltaH = -9...

`N_2(g) + 3H_2(g) to 2NH_3(g) , DeltaH = -92.3kJ`
`2NH_3(g) to N_2(g) + 3H_2(g) , Delta H = …….kJ`

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To solve the problem, we need to determine the enthalpy change (ΔH) for the reaction where 2 moles of ammonia (NH₃) decompose into nitrogen gas (N₂) and hydrogen gas (H₂). The given reaction is: \[ N_2(g) + 3H_2(g) \rightarrow 2NH_3(g) \quad \Delta H = -92.3 \, \text{kJ} \] ### Step-by-Step Solution: 1. **Identify the Given Reaction:** The reaction provided is: ...
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