Sucrose undergoes combustion as
`C_12 H_22 O_11 + 12 O_2(g) to 12CO_2(g) + 11 H_2O (l), DeltaH = -5643kJ`
How much energy will be liberated when 3.42 g of sucrose are burnt ?

Explanation

To determine how much energy will be liberated when 3.42 g of sucrose (C₁₂H₂₂O₁₁) is burnt, we can follow these steps:

### Step 1: Calculate the molar mass of sucrose (C₁₂H₂₂O₁₁)
- The molar mass is calculated using the atomic masses of carbon (C), hydrogen (H), and oxygen (O).
- Molar mass of sucrose = (12 × atomic mass of C) + (22 × atomic mass of H) + (11 × atomic mass of O)
- Atomic mass of C = 12 g/mol, H = 1 g/mol, O = 16 g/mol.

**Calculation:**
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