Calculate the heat of formation of methanol `(CH_3OH)` from thhe following data:
`CH_3OH(l) + 3/2O_2(g) to CO_2(g) + 2H_2O (l),Delta =-726 kJ`
`C(s) + O_2(g) to CO_2(g) ,`
`DeltaH = -394 kJ `
`H_2(g) + 1/2 O_2(g) to H_2O(l) , Delta H = -286 kJ`

Explanation

To calculate the heat of formation of methanol (CH₃OH) from the given data, we can use Hess's law, which states that the total enthalpy change for a reaction is the sum of the enthalpy changes for the individual steps of the reaction.

### Step-by-Step Solution:

1. **Write down the combustion reaction of methanol:**
\[ \text{CH}_3\text{OH}(l) + \frac{3}{2}\text{O}_2(g) \rightarrow \text{CO}_2(g) + 2\text{H}_2\text{O}(l) \quad \Delta H = -726 \text{ kJ} \]
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