The heat of neutralisation of NaOH and HCl is `57.3 kJ mol^(-1)` then the amount of heat liberated if 2 moles each of NaOH and HCl are reacted is

Options

A. 57.3 kJ mol
B. 114.6 kJ mol
C. 28.65 kJ mol
D. 215.2 kJ mol

Explanation

To solve the problem, we need to calculate the total heat liberated when 2 moles of sodium hydroxide (NaOH) react with 2 moles of hydrochloric acid (HCl). The heat of neutralization given is 57.3 kJ/mol.

### Step-by-Step Solution:

1. **Understand the Reaction**: The neutralization reaction between NaOH and HCl can be represented as:
\[ \text{NaOH} + \text{HCl} \rightarrow \text{NaCl} + \text{H}_2\text{O} \]
This reaction releases heat, which is known as the heat of neutralization.

2. **Identify the Heat of Neutralization**: The heat of neutralization for the reaction of 1 mole of NaOH with 1 mole of HCl is given as 57.3 kJ/mol.

3. **Calculate for 2 Moles**: Since the question asks for the heat released when 2 moles of NaOH react with 2 moles of HCl, we can use the following calculation:
\[ \text{Total heat} = \text{Heat of neutralization per mole} \times \text{Number of moles} \]
\[ \text{Total heat} = 57.3 \, \text{kJ/mol} \times 2 \, \text{moles} \]

4. **Perform the Calculation**:
\[ \text{Total heat} = 57.3 \times 2 = 114.6 \, \text{kJ} \]

5. **Consider the Sign**: Since the reaction is exothermic, the heat released is typically represented as a negative value. However, the question asks for the amount of heat liberated, so we can state:
\[ \text{Heat liberated} = -114.6 \, \text{kJ} \]
But for the purpose of this question, we can simply state the magnitude:
\[ \text{Heat liberated} = 114.6 \, \text{kJ} \]

### Final Answer:
The amount of heat liberated when 2 moles of NaOH react with 2 moles of HCl is **114.6 kJ**.

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