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For a cell involving one electron E(cell...

For a cell involving one electron `E_(cell)^(0)=0.59V` and 298K, the equilibrium constant for the cell reaction is:
[Given that `(2.303RT)/(F)=0.059V` at `T=298K`]

A

`1.0 xx 10^5`

B

`1.0 xx 10^10`

C

`1.0 xx 10^30`

D

`1.0 xx 10^2`

Text Solution

Verified by Experts

The correct Answer is:
B
`1.0 xx 10^10`
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