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The enthalpy change involved in the oxid...

The enthalpy change involved in the oxidation of glucose is `-2880 kJ mol^(-1)`. Twenty five per cent of this energy is available for muscular work. If 100 kJ of muscular work is needed to walk one kilometre, what is the maximum distance that a person will be able to walk eating 120 g of glucose ?

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To solve the problem, we need to follow these steps: ### Step 1: Calculate the number of moles of glucose consumed. Given: - Mass of glucose = 120 g - Molar mass of glucose (C₆H₁₂O₆) = 180 g/mol Using the formula: ...
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The enthalpy change involved in the oxidation of glucose is -2880kJ mol^(-1) . Twenty five per cent of this energy is available for muscular work . If 100kJ of muscular work is needed to walk one kilometre, what is the maximum distance that a person will be able to walk after eating 120g of glucose ?

Standard molar enthalpy of combustion of glucose is -2880 kJ. If only 25% of energy is available for muscular work and 1.0 km walk consumes 90 kJ of energy, what maximum distance (in km) a person can walk after eating 90 g of glucose.

If 150 kJ of energy is needed for muscular work to walk a distance of one km, than how much of gulcose one has to consume to walk a distance of five km, provided only 30% energy is available for muscular work.The enthalpy of combustion of glucose is 3000 kJ mol^(-1)

If 150 kJ of energy is needed for muscular work to walk a distance of one km, than how much of gulcose one has to consume to walk a distance of five km, provided only 30% energy is available for muscular work.The enthalpy of combustion of glucose is 3000 kJ mol^(-1)

The enthalpy of combustion of mol. Wt. 180 glucose is -2808 KJ "mol"^(-1) at 25^(@) C . X and Y grams of glucose do you need to consume respectively cases [Assume wt=62.5 Kg]. (a) to climb a flight of stairs rising through 3M. to climb a mountain of altitude 3000 M? Assume that 25% of enthalpy can be converted to useful work. X and Y are related as X=mY, then find m.

Animals operate under conditons of constant pressure and most of the process tht maintain life are isothermal ( in a broad sense) . How much energy is available for sustaining this type of muscular and nervous activity from the combustion of 1mol of glucose molecules under standard conditons at 37^(@) C (blood temperature) ? The entropy change is +182.4 JK^(-1) for the reaction stated above DeltaH_("combustion") [glucose]=-2808 KJ

Gasoline has an enthalpy of combustion 24000 kJ/mol gallon. When gasoline burns in an automobile engine, approximately 30% of the energy released is used to produce mechanical work. The remainder is lost as heat transfer to the engine's cooling system. As a start on estimating how much heat transfer is required, calculate what mass of water could be heated from 25^(@)C to 75^(@)C by the combustion of 1.0 gallon of gasoline in an automobile? (Given : C(H_(2)O)=4.18 J//g^(@)C )

An average person eats carbohydrates equivalent to 0.350 kg of glucose and 0.200 kg of fats every day. The person needs about 10000 kJ per day. If the body consumes carbohydrates preferentially, how much will his weight increase per year assuming that only 50% of the excess fats are excreted. Give that the heat of combustion of glucose is 2900 kJ and combustion of fats produces energy equivalent to 39000 kJ kg^(-1) ?

An athlete is given 180 g of glucose (C_(6)H_(12)O_(6)) . He utilises 50% of the energy due to internal combustion in the body. In order to avoid storage of energy in the body, calculate the masss of water he would need to perspire. Given enthalpy of combustion of glucose is -2800 kJ mol^(-1) and enthalpy of evaporation of water is 44 kJ mol^(-1)

An athlete is given 180 g of glucose (C_(6)H_(12)O_(6)) . He utilises 50% of the energy due to internal combustion in the body. In order to avoid storage of energy in the body, calculate the masss of water he would need to perspire. Given enthalpy of combustion of glucose is -2800 kJ mol^(-1) and enthalpy of evaporation of water is 44 kJ mol^(-1)

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