10 g of argon is compressed isothermally and reversibly at a temperature of `27^@C` from 10 L to 5L. Calculate , w, `DeltaE` and `DeltaH` for the process. `R = 2.0 cal K^(-1) mol^(-1), log 2 = 0.30,` At. Wt. of argon = 40.

Explanation

To solve the problem step by step, we will calculate the work done (W), change in internal energy (ΔE), and change in enthalpy (ΔH) for the isothermal and reversible compression of argon gas.

### Given Data:
- Mass of argon (m) = 10 g
- Initial volume (V1) = 10 L
- Final volume (V2) = 5 L
- Temperature (T) = 27°C = 300 K (after conversion)
- Gas constant (R) = 2.0 cal K^(-1) mol^(-1)
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